69 lines
3.4 KiB
Python
69 lines
3.4 KiB
Python
"""Sprunglabor ("jump lab"): measures how high/far the llama jumps (for parkour spacing).
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Lane A (z=20): steps of increasing height; lane B (z=26): gaps of increasing width."""
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LEVEL_ARGS = dict(name='Sprunglabor')
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def build(L):
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L.sea(0, 0, 60, 40, y=-2.0, kill=(4, 10, 56, 34))
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lane = L.opts.get('spur', 'a')
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if lane == 'f':
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# long jump over water (fall = respawn at start): start island, then 2-long blocks at the
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# same height with gaps 0.5/0.7/0.9/1.1/1.3; step lane g next to it (z=26): +0.2/+0.3 with 0.4
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L.box(8, 17, 14, 29, -1, 0, top='stein', side='stein_kante', rot=0)
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x = 14
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for i, gap in enumerate([0.5, 0.7, 0.9, 1.1, 1.3]):
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x += gap
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L.box(x, 18, x + 2, 22, -1, 0, top='holz_maser' if i % 2 == 0 else 'stein', side='stein_kante', rot=0)
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x += 2
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x, y = 14, 0.0
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for i, (gap, dy) in enumerate([(0.4, 0.2), (0.4, 0.2), (0.4, 0.3), (0.5, 0.2), (0.6, 0.2)]):
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x += gap; y += dy
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L.box(x, 24, x + 2, 28, -1, y, top='holz_maser' if i % 2 == 0 else 'stein', side='stein_kante', rot=0)
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x += 2
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L.player(11, 26 if L.opts.get('z') == 'g' else 20, rot=90)
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return
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L.box(10, 14, 50, 30, -1, 0, top='gras', side='erde', side_top='graskante')
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if lane == 'm':
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# coin measuring track: a coin every 0.25 from x=12 -> coin counter = distance travelled x4
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L.coins([(12 + 0.25 * i, 20) for i in range(int(L.opts.get('n', 112)))])
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L.player(11.5, 20, rot=90)
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return
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if lane == 'e':
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# measuring track: cross stripes every 1 unit (alternating white/red), llama at x=11.5
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for i in range(12, 48):
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L.floor(i, 19, i + 0.15, 21, 0.01, 'weiss' if i % 5 else 'rot', coll=False)
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L.player(11.5, 20, rot=90)
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elif lane == 'd':
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# gaps 0.5 / 0.75 / 1.0 / 1.25 between 0.6-high blocks (1.5 long each)
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L.box(10, 18, 14, 22, 0, 0.6, top='stein', side='stein_kante', rot=0)
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x = 14
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for i, gap in enumerate([0.5, 0.75, 1.0, 1.25]):
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x += gap
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L.box(x, 18, x + 1.5, 22, 0, 0.6, top='holz_maser' if i % 2 == 0 else 'stein', side='stein_kante', rot=0)
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x += 1.5
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L.player(11, 20, rot=90)
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elif lane == 'c':
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# single blocks of increasing height, 2 long each, 3 apart
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for i, h in enumerate([0.2, 0.35, 0.5, 0.7, 0.9]):
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x = 16 + i * 5
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L.box(x, 18, x + 2, 22, 0, h, top='holz_maser' if i % 2 else 'stein', side='stein_kante', rot=0)
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L.box(x - 0.1, 17.4, x + 0.1, 17.6, 0, 1.5, top='rot', side='rot', solid=False) # marker
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L.player(12, 20, rot=90)
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elif lane == 'a':
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# steps: heights 0.5, 1.0, 1.5, 2.25, 3.0 (2 deep each)
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x = 16
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for h, tex in [(0.5, 'stein'), (1.0, 'holz_maser'), (1.5, 'stein'), (2.25, 'holz_maser'), (3.0, 'stein')]:
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L.box(x, 18, x + 2, 22, 0, h, top=tex, side='stein_kante', rot=0)
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x += 2
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L.player(12, 20, rot=90)
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else:
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# gaps: platforms at 1.0, gaps 1.0, 1.5, 2.0, 2.5, 3.0
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x = 12
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L.box(x, 24, x + 4, 28, 0, 1.0, top='stein', side='stein_kante', rot=0)
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x += 4
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for gap in [1.0, 1.5, 2.0, 2.5, 3.0]:
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x += gap
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L.box(x, 24, x + 2, 28, 0, 1.0, top='holz_maser' if gap % 1 else 'stein', side='stein_kante', rot=0)
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x += 2
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L.player(13, 26, rot=90)
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